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Cake day: June 13th, 2023

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  • It’s quite easy, actually. I usually play everything years after release, however, if I’m really into a certain series, I’ll buy it right away. If I don’t care for the wait, I probably don’t care enough about whether or not a sequel is being made.

    Of course that only works if you don’t get hyped easily. I play a lot of games, but usually only 1-2 per year are released within said year.





  • I’ve come around to really liking them. In short, they vastly improve dungeons in my opinion.

    Most RPGs don’t manage to create interesting battles outside of boss fights. Heck, an increasing amount of RPGs fails to create any kind of challange. However, random encounter can add another layer to dungeons: resource management. You have to plan out how to tackle fights in order to get through the dungeons with your limited items/MP - do you sacrifice more HP or do you go for your strongest attacks? How much exploration can you get in? Do you need to be extra careful and plan for stronger rare encounters? Maybe even plan around lvl up healing.

    Sadly, this layer is easily removed. Overworld encounters? Just dodge everything. Adjustable encounters? Grind just enough, go heal and disable encounters. Non-challanging fights? Just use basic attacks. Healing stations? No need to plan anymore. Ideally, the dungeons provides no healing at all - especially not before encountering the boss.

    If you’re interested in a game with great dungeons, I’d recommend every single Etrian Odyssey.








  • De_Narm@lemmy.worldto196@lemmy.blahaj.zonePhysics rule
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    3 months ago

    I’m trying to apply the most simple math possible and it seems to add up.

    After one second, their distance is √(5² + 1²) = ~5.1 ft

    After two seconds, their distance is √(10² + 2²) = ~10.2 ft

    After three seconds, it’s √(15² + 3²) = ~15.3 ft

    As speed is the rate of change of distance over time, you can see it’s a constant 5.1 ft/s. You’re free to point out any error, but I don’t think you need anything more than Pythagoras’ theorem.

    The question specifically asks for their seperation speed at 5s to ignore any initial change in their speed as they first need to accelerate, I’d assume.


  • De_Narm@lemmy.worldto196@lemmy.blahaj.zonePhysics rule
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    3 months ago

    It’s been a while, but I think it’s quite trivial.

    After one second, they span a right angled triangle, therefore (using a² + b² = c²) their distance is √(5²+1²) = ~5.1 ft

    They move at constant speed, therefore they seperate at 5.1 ft/s. That means at 5s it’s just 5.1 × 5 = 25.5 ft for the distance and their speed is still the same.